Here is a rectangle that is 5 cm along the top and 2 cm down the side. Look at it carefully. Are any of its sides the same length as each other? Which ones? Do we really need to measure all four sides to find the distance all the way around, or could we be a bit cleverer about it?
Display a simple 5 cm × 2 cm rectangle on the board with the top and one side labelled. Take three hands-up answers, not open call-outs. Listen for a pupil noticing that opposite sides match — revoice it as the top equals the bottom, and the two sides are the same too. Don't reveal the shortcut yet; that lands in the next step.

This rectangle has all four sides added: 7 + 4 + 7 + 4 = 22 cm. The top and bottom are both 7, and the two sides are both 4. So we could add one of each first, 7 + 4 = 11, and then add that twice: 11 + 11 = 22 cm. Same answer, a smarter order.
A square has four equal sides. Instead of 9 + 9 + 9 + 9, we can count four nines: 4 × 9 = 36 cm.
This shape has five equal sides. Five fives: 5 × 5 = 25 cm. When every side is the same, we just multiply.
Walk each example aloud, one at a time.
After the rectangle's two methods, pause for a thumbs-up settle check: thumbs up if you can see why pairing the equal sides gives the same answer as adding all four. Let that land before you move to the multiplication shortcut for the square, so the two ideas don't blur together.
Pause after the pentagon and ask a pupil to predict the rule for a hexagon before you move on.
Here is a 6 cm by 3 cm rectangle on the board. Let's find its perimeter the smart way together. First, tell me which sides are equal. Then, instead of adding all four sides one slow side at a time, pair the equal sides: add one long side and one short side, then double it.
This round is for talking it through together. A pupil names the equal sides at the board, then the class agrees the quickest way to add them.
Ask the pupil at the board to name which sides are equal before adding (top and bottom are both 6 cm; the two sides are both 3 cm). Between the naming stage and the adding stage, do a quick turn-and-name across the room — pupils tell the person beside them which pairing they would add first — so the watching class stays with it. Then take the addition: 6 + 3 = 9, doubled is 18 cm. Revoice it as two of each, so add one pair and double it. If a pupil still adds all four one by one, accept it as a check but push them to also show the paired version. The square, triangle and pentagon variations are worked in the Class Challenge that follows — keep this beat to the single rectangle so the on-screen shape and your words stay in step.
In your maths copy, work out the perimeter of a 6 cm by 3 cm rectangle two ways. First add all four sides, one under the other. Then pair the equal sides: add one long side and one short side, and double your answer. Check that both ways give you exactly the same perimeter. When you have those, try the same two ways for an 8 cm by 5 cm rectangle.
Walk the room glancing at whether both methods land on the same total — this is whole-class copybook practice, not marking. A pupil who gets two different answers has a slip somewhere; prompt them to recount one method rather than telling them the answer. The second rectangle (8 + 5 = 13, doubled is 26 cm) gives fast finishers a genuine extra rather than waiting idle.
On the board is a 4 cm by 4 cm square. Spot the equal sides first, then find its perimeter the quickest way you can. After that, I will draw three more shapes for us to work the same way: a 10 cm by 6 cm rectangle, a regular hexagon with sides of 5 cm, and a regular octagon with sides of 7 cm. For each one, name the equal sides, then find the perimeter.
The square on screen (4 × 4 = 16 cm) is the first challenge. Once the class has it, draw the other three on the board in turn — the widget shows one shape, so the rectangle, hexagon and octagon are quick teacher sketches with their side lengths labelled. Pupils take turns naming the equal sides and the class confirms before moving on. Keep it brisk.
For each shape ask which sides are equal, and how does that speed up the adding? Answers: the 10 × 6 rectangle is 2 tens and 2 sixes, so 20 + 12 = 32 cm; the regular hexagon is 6 × 5 = 30 cm; the regular octagon is 8 × 7 = 56 cm. The hexagon and octagon are the stretch — fluent pupils reach for the multiplication straight away. The 10 × 6 rectangle is the one to watch for the slip of multiplying instead of pairing; revoice it as two tens and two sixes.
Why is a regular shape's perimeter so quick to find compared with a wobbly six-sided shape where every side is a different length? What is it about a regular shape that lets us use a times-table fact instead of adding side by side?
Listen for pupils naming the key idea: in a regular shape every side is the same, so the same number is added over and over, which is exactly what multiplication is. Revoice a strong answer as equal sides turn the adding into a times-table fact. Head off the misconception that the shortcut works for any shape — it only works when sides are equal; an irregular shape still needs every side added. Draw an irregular six-sided shape with six different lengths and ask whether the multiplication shortcut would work, so the limit of the rule is clear before the lesson ends.
Next we move from the distance around a shape to the flat space inside it. We will start measuring area by counting the square units that cover a shape.
Keep this brisk. Re-state the one big idea: equal sides let us multiply instead of adding slowly. Flag the shift coming next from perimeter (around the edge) to area (the space inside) so pupils don't muddle the two.
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